This sheet gives the value of friction factor f from the Colbrook-White, Moody and Barr formuleaEnter the parameters in the coloured boxesColebrook white MoodyBarrEnter the parameters hereks (mm) 0.03d (mm) 300Re 664000olution f !Moody 0.003018 0.012072Barr 0.0031 0.01406Colebrook-White 0.0034! 0.013!8Colebrook"#hite iteratio$%($) a b &'( R'( )rror *1 0.003018 2.6!42)"00 3.)"00 18.202!7 16.84461 1.3832 0.0120722 0.00324 2.6!42)"00 3.2)"00 16.84461 16.!1! "0.074384 0.0140!73 0.0034!3 2.6!42)"00 3.2)"00 16.!1! 16.!1484 0.00417 0.013!744 0.0034! 2.6!42)"00 3.2)"00 16.!1484 16.!107 "0.000232 0.013!81 0.0034! 2.6!42)"00 3.2)"00 16.!107 16.!106 1.3)"00 0.013!86 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 "7)"007 0.013!87 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 4.0)"008 0.013!88 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 "2)"00! 0.013!8! 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 1.3)"010 0.013!810 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 "7)"012 0.013!811 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 3.!)"013 0.013!812 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 0 0.013!813 0.0034! 2.6!42)"00 3.2)"00 16.!106 16.!106 0 0.013!81f =4 log10(ks3. 71d + 1. 26Re f )f n+1=1/[4 log10(ks3. 71d+ 1. 26Ref n )]2f n+1=1[4 log10 ( a+b)]2f =0. 001375[1+(200ksd+106Re )1/ 3]1f =4 log10[ks3. 71d+5. 1286Re0. 89 ]f =1/[4 log10(ks3. 71d +5. 1286Re0 . 89 )]2This sheet gives the value of friction factor f from the Colbrook-White, Moody and Barr formuleaf =0. 001375[1+(200ksd+106Re )1/ 3]1f =4 log10[ks3. 71d+5. 1286Re0. 89 ]f =1/[4 log10(ks3. 71d +5. 1286Re0 . 89 )]2