Find force in member EF, HI

Moment of Inertia

Parallel Axis Theorem: IXX=I X+A dy2 I yy=I y+Adx

2

IX : From the table in the back of your textbookdx ,dy❑ :Distance between centroid of the part and the centroid of the whole object

Shape Area IX I y dx dy Adx2 Ady2

Rectangle ab 112bh3 1

12hb3 = |x−xc| = |y− yc|

Circle π r2 14πr 4 1

4πr 4

Triangle 12bh

136bh3 1

36hb3

Sum up the total values and apply into the equations: IXX=I X+A dy2 I yy=I y+Adx

2

radius of gyration: kx=√❑ ky=√❑ polar moment of inertia: J=I xx+ I yy