3 - 1 © 2012 Pearson Education, Inc.. All rights reserved. Chapter 3 The Derivative.

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Transcript of 3 - 1 © 2012 Pearson Education, Inc.. All rights reserved. Chapter 3 The Derivative.

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Chapter 3

The Derivative

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Section 3.1

Limits

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Figure 2

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Notation *from Spivak’s Calculus

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Your Turn

Solution: since

The numerator also approaches 0 as x approaches −3, and 0/0

is meaningless. For x ≠ − 3 we can, however, simplify the

function by rewriting the fraction as

Now

2

3

12Find lim .

3x

x xx

3lim 3 0.x

x

2 12 ( 4)( 3)4.

3 ( 3)x x x x

xx x

2

3 3

12lim lim 4

3x x

x xx

x

3 4 7.

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Left and Right

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Left and Right

What can you say about lim f(x) as x 10 if lim f(x) as x 10- (from the left) is 5 lim f(x) as x 10+ (from the right) is 5 ?

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infinity

lim 1/x as x infinity ?

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Two Tools with Limits

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Your Turn 5

Suppose

and

find

Solution:

2lim ( ) 3x

f x

2lim ( ) 4.x

g x

2

2lim[ ( ) ( )] .x

f x g x

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Your Turn 8

Solution: Here, the highest power of x is x2, which is used to divide

each term in the numerator and denominator.

2

2

2 3 4Find lim .

6 5 7x

x xx x

2 2 2

2

2

2

2

2

2 3 4

lim6 5 7x

x x x

x x x

x x

x x

2

2

3 42

lim 5 7

6x

x x

x x

2 1

60

31

lim nx x

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Your Turn

2 1

60

31

lim nx x

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Section 3.2

Continuity

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Figure 14

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Figure 15 - 16

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Figure 17

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Your Turn 1

Find all values x = a where the function

is discontinuous.

Solution: This root function is discontinuous wherever the

radicand is negative.

There is a discontinuity when 5x + 3 < 0

( ) 5 3f x x

3.

5x

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Your Turn 2

Find all values of x where the piecewise function is discontinuous.

Solution: Since each piece of this function is a polynomial, the

only x-values where f might be discontinuous here are 0 and 3.

We investigate at x = 0 first. From the left, where x-values are less

than 0,

From the right, where x-values are greater than 0

Continued

2

5 4 if 0

( ) if 0 3

6 if 3

x x

f x x x

x x

0 0lim ( ) lim 5 4 4.x x

f x x

2

0 0lim ( ) lim 0.x x

f x x

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Your Turn 2 Continued

Because

the limit does not exist, so f is discontinuous at x = 0 regardless

of the value of f(0).

Now let us investigate at x = 3.

Thus, f is continuous at x = 3.

0 0lim ( ) lim ( )x x

f x f x

2

3 3lim ( ) lim 9.x x

f x x

3 3lim ( ) lim 6 9.x x

f x x

2Furthermore, (3) 3 9.f

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Figure 20

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Figure 21

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Figure 22

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Section 3.3

Rates of Change

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Figure 23

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Section 3.4

Definition of the Derivative

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Figure 27

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Figure 31

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Figure 32

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Figure 33 - 34

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Figure 36 - 37

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Figure 38

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Figure 39

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Figure 40

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Figure 41 - 42

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Figure 44

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Section 3.5

Graphical Differentiation

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Chapter 3

Extended Application: A Model for

Drugs Administered Intravenously

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