11X1 T08 02 first principles

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Transcript of 11X1 T08 02 first principles

The Slope of a Tangent to a Curve

The Slope of a Tangent to a Curvey

x

y f x

The Slope of a Tangent to a Curvey

x

P

y f x

k

The Slope of a Tangent to a Curvey

x

P

y f x

k

Q

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

Q: Where do we position Q to get the best estimate?

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

Q: Where do we position Q to get the best estimate?

A: As close to P as possible.

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

Q: Where do we position Q to get the best estimate?

A: As close to P as possible.

P

Q

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

Q: Where do we position Q to get the best estimate?

A: As close to P as possible.

P

Q

,x f x

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

Q: Where do we position Q to get the best estimate?

A: As close to P as possible.

P

Q

,x f x

,x h f x h

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

Q: Where do we position Q to get the best estimate?

A: As close to P as possible.

P

Q

,x f x

,x h f x h

PQf x h f x

mx h x

f x h f xh

The Slope of a Tangent to a CurveSlope PQ is an estimate for the slope of line k.

y

x

P

y f x

k

Q

Q: Where do we position Q to get the best estimate?

A: As close to P as possible.

P

Q

,x f x

,x h f x h

PQf x h f x

mx h x

f x h f xh

To find the exact value of the slope of k, we calculate the limit of the slope PQ as h gets closer to 0.

0

slope of tangent = limh

f x h f xh

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised;

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles”

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

6 1f x x

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

6 1f x x

6 16 6 1

f x h x hx h

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

6 1f x x

6 16 6 1

f x h x hx h

0

limh

f x h f xdydx h

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

6 1f x x

6 16 6 1

f x h x hx h

0

limh

f x h f xdydx h

0

6 6 1 6 1limh

x h xh

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

6 1f x x

6 16 6 1

f x h x hx h

0

limh

f x h f xdydx h

0

6 6 1 6 1limh

x h xh

0

6limh

hh

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

6 1f x x

6 16 6 1

f x h x hx h

0

limh

f x h f xdydx h

0

6 6 1 6 1limh

x h xh

0

6limh

hh

0lim6h

the derivative measures the rate

of something changing

0

slope of tangent = limh

f x h f xh

This is known as the “derivative of y with respect to x” and is symbolised; dy

dx, y , f x , d f x

dx

0

limh

f x h f xf x

h

The process is called “differentiating from first principles” e.g. Differentiate 6 1 by using first principles.i y x

6 1f x x

6 16 6 1

f x h x hx h

0

limh

f x h f xdydx h

0

6 6 1 6 1limh

x h xh

0

6limh

hh

0lim6h

6

the derivative measures the rate

of something changing

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

0

limh

f x h f xdydx h

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

0

limh

f x h f xdydx h

2 2 2

0

2 5 5 2 5 2limh

x xh h x h x xh

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

0

limh

f x h f xdydx h

2 2 2

0

2 5 5 2 5 2limh

x xh h x h x xh

2

0

2 5limh

xh h hh

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

0

limh

f x h f xdydx h

2 2 2

0

2 5 5 2 5 2limh

x xh h x h x xh

2

0

2 5limh

xh h hh

0lim 2 5h

x h

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

0

limh

f x h f xdydx h

2 2 2

0

2 5 5 2 5 2limh

x xh h x h x xh

2

0

2 5limh

xh h hh

0lim 2 5h

x h

2 5x

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

0

limh

f x h f xdydx h

2 2 2

0

2 5 5 2 5 2limh

x xh h x h x xh

2

0

2 5limh

xh h hh

0lim 2 5h

x h

2 5x

when 1, 2 1 5

3

dyxdx

2 Find the equation of the tangent to 5 2 at the point 1, 2 .ii y x x

2 5 2f x x x 2 5 2f x h x h x h

2 22 5 5 2x xh h x h

0

limh

f x h f xdydx h

2 2 2

0

2 5 5 2 5 2limh

x xh h x h x xh

2

0

2 5limh

xh h hh

0lim 2 5h

x h

2 5x

when 1, 2 1 5

3

dyxdx

the slope of the tangent at 1, 2 is 3

2 3 1y x

2 3 1y x

2 3 33 1

y xy x

2 3 1y x

2 3 33 1

y xy x

Exercise 7B; 1, 2adgi, 3(not iv), 4, 7ab i,v, 12 (just h approaches 0)